CS152 2004F : Homework 22: Fibonacci Computation, Revisited

public long fib(int n)
{
   long[] values = new long[n+1];
   values[0] = 0;
   values[1] = 1;
   for (int i = 2; i <= n; i++)
   {
      values[i] = values[i-1] + values[i-2];
   } // for(int)
   return values[n];
} // fib(int)

Unfortunately, we run out of longs fairly quickly. Hence, we would benefit from returning a BigInteger and doing our intermediate computations with BigIntegers. Rewrite the code to do just that.

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Samuel A. Rebelsky, rebelsky@grinnell.edu